Question

find the domain of f(x)^-1if f(x)=7x+3

Answer 1

\[f(x)^{-1}=\frac{1}{7x+3}\]
find the value of x for which denominator is zero
7x+3=0
7x=-3
x=-3/7
at x=-3/7 th value of f(x)^-1 is undefined, so domain is all real numbers -{-7/3}

Answer 2

\[f(x)^{-1}=\frac{1}{7x+3}\]
\[7x+3\neq0, 7x \neq -3, x \neq \frac{-3}{7}\]
\[(-\infty, \frac{-3}{7})U(\frac{-3}{7}, \infty)\]

Answer 3

thanksssss