Question

Solve for x: (4overX)+(4overX^2-9)=(3overX-3)

Answer 1

\[{4 \over x}+{4 \over x^2-9}-{3 \over x-3}={4(x^2-9)+4x-3x(x+3) \over x(x^2-9)}.\]
The expression is 0 when the numerator equals 0. You need now to solve the quadratic equation

\(4(x^2-9)+4x-3x(x+3)=x^2-5x-36=0\).

Answer 2

answer?

Answer 3

please

Answer 4

x=4 and x=-9?

Answer 5

x=-4 or x=9.

Answer 6

thanks