Question

y(s)=1/5s^2 - 6/s
find y'(s)

Answer 1

is s^2 in the denom? and s too?

Answer 2

let me rewrite

Answer 3

is this your equation:\[y(s)=\frac{1}{5s^2}-\frac{6}{s}\]

Answer 4

y(s)=(1)/(5s^2) - (6)/(s)

Answer 5

YES!

Answer 6

sorry about the confusion everyone

Answer 7

i see...well the constants don't affect the differentiation..just turn the s to negative exponents then power rule. try

Answer 8

you also dont have to LCD it or anything...itll just make it harder

Answer 9

yes - Igbasallote is correct. rewrite the equation as:\[y(s)=\frac{1}{5}s^{-2}-6s^{-1}\]you should then be able to use the standard rules of differentiation.

Answer 10

i.e. use the rule that if:\[y=ax^b\]then:\[y'=abx^{b-1}\]

Answer 11

do you understand?

Answer 12

YES IT DOES! THANKS!

Answer 13

yw

Answer 14

:D