Question

How much energy is stored on a 23-μ F capacitor that is charged to a potential difference of 40 Volts?

Answer 1

The energy in a capacitor is given by
\[ U = \frac{1}{2}QV = \frac{1}{2}CV^2 \] Now you have C and V, so you have your answer.

Answer 2

U is the energy. C is the capacitance. V is the voltage. Just make sure you put C and V in SI units.

Answer 3

to get it to F from the u-F is the constant10^6?

Answer 4

micro Farad. Not mega Farad!

Answer 5

so 10^-6

Answer 6

oh whoops! thanks!

Answer 7

I still am not getting the correct answer I am doing (23*10^-6)*40^2*.5

Answer 8

That's 0.0184 J.

What's the supposed answer?

Answer 9

It is saying J isnt the right units

Answer 10

Nevermind I wasnt typing it in correctly i was using 1.84*10^2 instead of -2

Answer 11

Good