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Mathematics 7 Online
OpenStudy (anonymous):

how to determine the min of an equation?

OpenStudy (anonymous):

? an equation does not have a minimum. it has a solution perhaps

OpenStudy (anonymous):

no it says determine the minimum

OpenStudy (anonymous):

well let's see your *function

OpenStudy (anonymous):

y=345.14t^2-1705.65t+42903.6 t= 0 represents 1999

OpenStudy (anonymous):

take the first derivative and set it = 0

OpenStudy (anonymous):

hu???

OpenStudy (anonymous):

is this a calculus question?

OpenStudy (anonymous):

no

OpenStudy (anonymous):

minimum is the second coordinate of the vertex. first coordinate is \[-\frac{b}{2a}\] but i'll be damned if i can compute it with these ridiculous decimals. use a calculator

OpenStudy (anonymous):

so okay the only thing is to plug them in right

OpenStudy (anonymous):

apparently it is \[\frac{112643504187}{2761120}\]at t = 170565\/69028

OpenStudy (anonymous):

i thought it was 1705.65/2(345.14)

OpenStudy (anonymous):

is it not?

OpenStudy (anonymous):

you're right cherry

OpenStudy (anonymous):

dy/dx = 690.28t-1705.65 690.28t-1705.65 = 0 t=1705.65/690.28

OpenStudy (anonymous):

dy/dt*

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