Question

b²-16b+64=16 SOLVE PL0X

Answer 1

we have
\[b^2-16b+64=16\]
subtract both sides by 16
\[b^2-16b+48\]
let's find factors of 48 ,which sums up to -48
-12 and -4
-12+(-4)=-16
-12*-4=48
so we have now
\[b^2-12b-4b+48\]
\[b(b-12)-4(b-12)\]
we get finally
\[(b-4)(b-12)\]
so the roots are b=4 and b=12

Answer 2

woops, i didnt see the 16, lol.
im blind xD

Answer 3

thanks