In physics what is a field? A) the immediate space around a charge, mass or magnet b) a region in which something experiences a force C) the space in which objects are able to move D) The region between two charges, masses or magnets
I think its B but im not 100% positive
I would say C.
the larger the object the more field lines? is that true?
A field is associated with the plotting of spacetime. C is the only answer that is general enough to cover this fact. Generally speaking, yes, the larger the object the "more" field there is.
B
... Proof, for those who disagree. http://en.wikipedia.org/wiki/Field_%28physics%29
Define the concept of a gravitational field?
It's a field that is caused due to the bump in spacetime caused by mass. Sort of hard to imagine in 3D.
That is by no means a definition. It's just to give you an idea.
A field where the acceleration of gravity acts as a force on all bodies inside. Alternatively, a field that is a geodesic, in terms of general relativity.
Doesn't he mean the origin of gravity?
"The concept of a gravitational field". The field itself, not the mass. But you covered for that anyways, so I'm not worried. ;D
What would be the gravitational field at the midpoint between, and due to two identical planets? explain
Be a zero net force. Nearly impossible in reality. It would just stay in position.
Thanks guys! I have a few more questions :)
An object of mass 12kg weighs 156 N on planet X. what is the magnitude of the acceleration due to gravity on planet x
F = ma a = F/m 156/12 = something
What LordHades said. I'm just piggybacking his medals.
how might this planet differ from Earth?
Well, its acceleration due to gravity is much higher, so it's probably of a greater mass.
And you;ll weigh heavier there.
12*9.81= 117.6N
Note that I'm talking about weight not mass.
that would be on earth, so you are lighter on earth
yes,
The Earth has a mass of 6x10^24kg and a diameter of 12,765 km. A 500kg satellite experiences a gravitational acceleration of 0.4 ms^-2 in its orbit. What is the altitude of the satellite?
M = 6 x 10^24 re = 6382.5 m = 500 ac = 0.4 ac = v^2/r r = v^2 / ac -------->1 GMm/r^2 = mv^2/r ------------>2 From 1 and 2, Solve for 'v' and then get 'r' Should work I think, tell me if I messed up somewhere.
List of possible answers a) 2.53 x10^7 m b) 3.16 x 10^7 m c) 2.80 x 10^8 m d) 2.86 x 10^8m
From here on it's just calculations and algebra, nothing difficult.
At what altitude would a 1000kg satellite be to experience the same gravitational acceleration? Explain
You could use the exact same formulae, just need to rearrange the variables.
I dont have a calculator with me :(
Doubling the mass, yet keeping the acceleration the same, is multiplying both sides of the equation by 2.
The force vector of the satellite, the one we're concerned with, doubles, right? Yeah. The mass of the satellite also doubles.
do you know about the Lagrange points in a feild?
no... what are they?
the stable points, for example in the sun earth system there are 5 stable points (places where gravitational attraction is balanced)|dw:1329366257688:dw|
Join our real-time social learning platform and learn together with your friends!