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Find the derivative of the function. y = e^x − e^(−x) / 5 y'=
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\[y=e^x-{e^{-x}\over 5}\]\[y'=e^x+{e^{-x}\over5}\]
\[y=\]\[(e ^{x}-e ^{-x})\div5\]
i think my parentheses were confusing
my apologies
oh i see now
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\[y(x)={e^x-e^{-x} \over 5}\] \[y'(x)={e^x +e^{-x} \over 5}\]
why did only the sign change?
well the thing about derivatives of e is they are easy \[(e^x)'=e^x\] \[(e^{ax})'=ae^{ax}\]
the second in exponential term a=-1
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