Can someone explain when functions are continuous, differentiable and defined?
continuous when \[\lim_{x \rightarrow c^-}f(x) = lim_{x \rightarrow c^+}f(x)\]\[\lim_{x \rightarrow c}f(x) = f(c)\]f(c) is defined, that is the denominator does not equal 0
um, not quite sure how to say when something's differentiable...
CONTINUOUS - no gaps in valid x values, no vertical asymptotes, no point (hole) discontinuities, nowhere the function is undefined. DIFFERENTIABLE - essentially this means SMOOTH, no pointy bits. Polynomials, trig functions, summations of those two combined like taylor series, Maclauren series etc.... tha'ts why those series are used. Log & exponentials are smooth too. A function will not be differentiable at a point where the DERIVATIVE is discontinuous, because that means the gradient of the function approaching the point from one side has a different value as you approach the point from the other side - so you get a pointy bit! DEFINED - you can actually evaluate the function. A function is NOT DEFINED where you have 0 in the bottom of a fraction, where you have a negative under a square root, where you have a negative as the argument of a log etc....
The deriveative is the gradient - so pointy bits don't have a defined gradient (slope of the tangent) - which side to you take the tangent from, as you approach the point? Get it?
so a function is always continuous where it is differentiable, but not always differentiable where it is continuous?
and if it's not differentiable, then it's not defined?
Sorry - I'm in a different tim-zone to you. A function can be continuous, but not differentiable (has a pointy bit), but it is not differentiable at a point discontinuity, or at the end points of a non-point gap discontinuity. If a function is differentiable over an interval, then it MUST automatically be continuous over that same interval. Differentiable means it IS continuous. Continuous does not necessarily means it's differentiable.
A function can be said continous if L.H.L=R.H.L. i.e. left hand limit =right hand limit Mathematical expr.. \[\lim_{h \rightarrow 0}f(x-h)=\lim_{h \rightarrow0}f(x+h)\] where h = the number value around which you need to show the continuity of a function For a function to be differentiable \[\lim_{h \rightarrow0}(f(x-h)-f(x))/(-h)=\lim_{h \rightarrow 0}(f(x+h)-f(x))/h\] Where h = the number value around which you need to show the diferentiability. of a function.hope you understand,if not ask
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