Question

does this work:
r=-4 sin theta
4=-r sin theta
Something makes me feel like this doesn't work but I have to check.

Answer 1

what's your purpose?

Answer 2

trying to convert from polar form to cartesian. My next step would be to substitute x in where x=r cos theta

Answer 3

No. it doesn't work.

Answer 4

to check, consider this:

30 = 6 * 5

6 = -30 * 5

Answer 5

cartesian needs an r^2 and some sort of r sin, or r cos to play with

Answer 6

(r=-4 sin(t) ) *r

r^2 = -4 rsin(t)

since r^2 = x^2 + y^2; and y = r sin(t) we get:

x^2 + y^2 = -4y

or so ive been led to believe