Question

If H(x)=sqrt(x+12)

Find H'(x)

Answer 1

\[H(x)=f(g(x))=> H'(x)=f'(g(x))g'(x)\]
where g(x)=x+12 and f(x)=x^(1/2)

Answer 2

so what would the final answer be?
sorry, i havent gotten this stuff down yet. need as much help as possible.

Answer 3

use what i gave you to find H'
g'(x)=1
f'(x)=1/2 * x^(-1/2)
no plug g(x) into f'(x) yo fin f'(g(x)
and then don't forget to multiply that by g'(x)=1

Answer 4

why is g'(x)=1
shouldn't it be x?

Answer 5

?

Answer 6

because g=x+12
g'=1 since the slope of x+12 is 1

Answer 7

and after i do what you said i get 1/2(x+12^(-1/2)) but thats not the final answer according to my hw website

Answer 8

no it is not you have to simplify you need to close a parantheis too

Answer 9

you put the paranthesis in the wrong spot

Answer 10

after you fix that write your answer so that any exponents are positve

Answer 11

\[\frac{1}{2}(x+12)^\frac{-1}{2}=\frac{1}{2} \cdot \frac{1}{(x+12)^\frac{1}{2}}\]
\[\frac{1}{2\sqrt{x+12}}\]

Answer 12

i seem to be putting it in wrong. how would i put it in the old school way?

Answer 13

1/[2(x+12)^(1/2)]

Answer 14

ok thanks. sorry for all the trouble.