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Mathematics 7 Online
OpenStudy (anonymous):

integrate by parts: ʃ sinx lnx

OpenStudy (turingtest):

I don't think this is expressible in terms of elementary functions

OpenStudy (amistre64):

can you cycle it back around?

OpenStudy (amistre64):

sin(x) + ln(x) cos(x) - 1/x -sin(x) hmmm

OpenStudy (turingtest):

the way I see it: dv=sin x u=lnx u never goes away the other way, u=lnx, does not seem promising, but give it a try :D

OpenStudy (turingtest):

the other way dv=lnx I mean...

OpenStudy (amistre64):

ln(x) ups to what: xln(x) - x i think

OpenStudy (anonymous):

lnx cant be integrated right?

OpenStudy (amistre64):

yes, lnx can be integrated

OpenStudy (amistre64):

xlnx - x derives to ln(x) + x/x - 1 = ln(x)

OpenStudy (amistre64):

\[\int sin(x)ln(x)dx= sin(x)(xln(x)-x) - \int cos(x)(xlnx-x) dx\] \[\int cos(x)(xlnx-x) dx=\int xcos(x)ln(x)-xcos(x)\ dx\]

OpenStudy (amistre64):

its ugly, but might be doable overall

OpenStudy (anonymous):

lnx cant be differentiated?

OpenStudy (amistre64):

otherwise: \[\int sin(x)ln(x)dx=cos(x)ln(x)-\int \frac{cos(x)}{x}dx\]

OpenStudy (amistre64):

really? ln(x)' = 1/x

OpenStudy (amistre64):

you need to brush up on this stuff i assume lol

OpenStudy (anonymous):

lnx cant be integrated im sure. it is non-integrable

OpenStudy (turingtest):

lnx is totally integrable by parts, as amistre did above

OpenStudy (turingtest):

\[\int \ln xdx\]\[u=\ln x\]\[dv=1\]try it!

OpenStudy (anonymous):

differntial of lnx=1/x.... but what is the answer of integral of lnx? just the final answer?

OpenStudy (turingtest):

um... the final answer is the final answer, not sure what you mean

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