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After 8ml of phosphate addition the height becomes costant this implies that all the metal nitrate added can be reacted by adding 8ml of phosphate. now millimoles of phosphate=8. Millimoles of nitrate=12. 3T(NO3)x + x Na3(PO4)-> T3 (PO4)x +3x NaNO3 12 8 3/x=12/8. 3/x=3/2. x=2, So the formula is T (NO3)2
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