Mathematics
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OpenStudy (anonymous):
Write these series with summation notation.
1) 1+4+7+ . . . +19
2) 1, 4, 9, 16, . . .
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OpenStudy (anonymous):
\[\sum_{i=1}^{19} i+3 \]
OpenStudy (anonymous):
2) is not a series.
OpenStudy (amistre64):
its a seq of perfect squares tho
OpenStudy (anonymous):
For 2)?
OpenStudy (anonymous):
Yes, we all can see \(8^2\) in amistre64
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OpenStudy (amistre64):
woohoo!! i thought i was the only one :)
OpenStudy (anonymous):
lol, you are taken after all.
OpenStudy (anonymous):
lol
OpenStudy (anonymous):
mugwump101 answer is incorrect.
OpenStudy (anonymous):
I think you can write number 2 as a series though, can't you?
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OpenStudy (anonymous):
Really? why?
OpenStudy (amistre64):
you cant sum a series that isnt a series
OpenStudy (amistre64):
there aint 19 terms
OpenStudy (amistre64):
1 to ..... not 19
OpenStudy (amistre64):
16+3 = 19; 19+3 not= 19
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OpenStudy (amistre64):
and 2+3 = 5 not 4
OpenStudy (amistre64):
its just all messed up lol
OpenStudy (anonymous):
Here is the answer \( \large \sum \limits_{n=1}^{7} 3n-2 \)
OpenStudy (amistre64):
\[\sum_{i=1}^{}-2+3(i)\]yeah that thinkg
OpenStudy (anonymous):
That makes alot more sense, thanks fellas. :)
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OpenStudy (anonymous):
amstre you are slow :P
OpenStudy (amistre64):
its this accursed IE im playing n; and my old brain i have to work with too lol
OpenStudy (anonymous):
LOL I see. Thanks for your input XD