Find values for a and b in the equation ax^2-b=14 such that the solutions will be complex solutions.

Question

asnaseer · Answer

ok, first write this in the standard form as:$$ax^2-bx-14=0$$I am assuming you missed the "x" from the b in your question above.

anonymous · Answer

Not necessarily lol.
There is no x besides b.

asnaseer · Answer

ok, in that case we have:$$ax^2=14+b$$

asnaseer · Answer

which leads to:$$x^2=\frac{14+b}{a}$$for this to give complex solutions we need:$$\frac{14+b}{a}\lt0$$

asnaseer · Answer

because that would lead to generating a square root of a negative number which gives complex results

anonymous · Answer

I see now.. :)
Thanks

asnaseer · Answer

you will need to find two inequalities here

anonymous · Answer

Indeeds.

asnaseer · Answer

ok - good - you DO understand :)

anonymous · Answer

Course! :)

asnaseer · Answer

great! it's just that it's difficult to judge how much each user already knows on a site like this.

anonymous · Answer

I understand :)
Many levels of understanding in this site so it's a bit difficult.

asnaseer · Answer

but its great we have people like you who actually put in the effort of learning rather than just asking for answers.

anonymous · Answer

Oh I know, they just look for answers to input their answers and ask away next question.. I for one put in the effort to at least learn something, not just wasting peoples time :)

asnaseer · Answer

You will go far - wish you all the success in your life my friend.

anonymous · Answer

Much appreciated friend! I bid you the same.

asnaseer · Answer

thx - take care