Find the polynomial f(x) that has the roots of –2, 3 of multiplicity 2. Explain how you would verify the zeros of f(x).

I dont get it, can anyone please help me?

Question

Find the polynomial f(x) that has the roots of –2, 3 of multiplicity 2. Explain how you would verify the zeros of f(x).  

I dont get it, can anyone please help me?

amistre64 · Answer

(-2+2) (3-3)^2

(x+2) (x-3)^2

anonymous · Answer

can you please explain?

amistre64 · Answer

which part?

what a zero is?  how to form a zero from roots?  why zeroed roots equal zero?  or some other ?

amistre64 · Answer

if i knew where your confusion lie, I could try to help you thru it

asnaseer · Answer

if a polynomial has three roots, lets call them $r_1, r_2, r_3$, then it can be expressed as:$$f(x)=(x-r_1)(x-r_2)(x-r_3)=0$$

amistre64 · Answer

they might be back ....

asnaseer · Answer

in your case, two of the roots are the same, so lets sat $r_3=r_2$, this would lead to:$$f(x)=(x-r_1)(x-r_2)^2=0$$
which is what amistre was showing you.

amistre64 · Answer

the latex freezez up the IE

asnaseer · Answer

and on chrome as well - I get round it for now by entering a newline after I have typed it up - that seems to force it to render.