Question

Can someone explain how this was simplified from \[\frac{\sqrt{320t ^{2}+4096}}{(64+5t ^{2})^{\frac{3}{2}}}\] to this \[\frac{8}{(64+5t ^{2})}\]?

Answer 1

factor out 64 from the numerator...

Answer 2

\[8\frac{(64+5t^2)^{1/2}}{(64+5t^2)^{3/2}}=\frac8{64+5t^2}\]

Answer 3

oh gotcha
nvm

Answer 4

jeezum

Answer 5

Thnaks

Answer 6

To much mathematica is making me slowwwwwww

Answer 7

no prob, algebra can be tricky at times ;)