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Mathematics 22 Online
OpenStudy (anonymous):

let me rephrase, classify the triangles with given side lengths as right acute or obtuse,, the problem i need help with is 6,,6,10

Directrix (directrix):

Obtuse. 10^2 is greater than the sum of 6^2 and 6^2

OpenStudy (anonymous):

how bout 6,10,10

OpenStudy (anonymous):

hmm maybe theres a faster way i can through the problems without asking one by one what is the process of getting the answer?

Directrix (directrix):

Obtuse. If 3 segments have lengths that can be sides of a triangle (see Triangle Inequality Theorem), then if the square of one of the sides is greater than the sum of the squares of the other two sides, the triangle is obtuse.

OpenStudy (anonymous):

sqrt 6, sqrt 8 sqrt 10 is it right acute or obtuse

Directrix (directrix):

The first task is to see if these lengths can be the sides of any triangle. Test to ensure that one side is less than the sum of the other two.

Directrix (directrix):

Suppose you had the sides 1, 2, and 3 (lengths). They cannot be sides of a triangle but if you did not check you would think they formed an obtuse triangle. That would be wrong.

OpenStudy (anonymous):

how do you check or know if they are sides of a triangle

Directrix (directrix):

Triangle Inequality Theorem. On the 1, 2, 3, example, Is 1 < (2+3) Yes Is 2 < (1 + 3) Yes Is 3 < (1 + 2) NO so these lengths cannot be sides of a triangle.

Directrix (directrix):

You check to see if sqrt 6, sqrt 8 sqrt 10 can be sides of a triangle.

OpenStudy (anonymous):

ohhhh ok i understand let me solve these problems real quick

Directrix (directrix):

The triangle inequality theorem states that any side of a triangle is always shorter than the sum of the other two sides. http://www.mathopenref.com/triangleinequality.html

OpenStudy (anonymous):

oh, if it is not then it none of the classidications

OpenStudy (anonymous):

wait woah im confused so how will i know what to classify the trianglesqrt 6 , sqrt 8, sqrt 10 as acute right or obtuse?

OpenStudy (anonymous):

Yes

Directrix (directrix):

First you have to answer the question: sqrt 6, sqrt 8 sqrt 10 can be sides of a triangle. YES or NO? You say Yes. Then, take the longest side √ 10 and determine if its square is greater than the sum of the squares of √ 6 and √ 8.

Directrix (directrix):

10> 6 + 8 NO 10< 14 Yes. The triangle is acute.

OpenStudy (anonymous):

i think you might have missed to put sqrt, sqrt 10 is greater then sqrt 6 + sqrt 8

Directrix (directrix):

No. The square of square root 10 is just 10.

OpenStudy (anonymous):

Geometry is so difficult i should have taken alrebra 2, ok.. i did my next problem 6, 8 , 10 none of them are sqrt's would they be acute also

Directrix (directrix):

You must use the theorem. 10^2 = 6^2 + 8^2 Triangle is RIGHT. Hold on while I find the theorem.

Directrix (directrix):

If the square of the longest side of a triangle is greater than the sum of the squares of the other two, then the triangle is obtuse. If the square of the longest side of a triangle is equal to the sum of the squares of the other two, then the triangle is right. If the square of the longest side of a triangle is less than the sum of the squares of the other two, then the triangle is acute.

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