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Integrate sec(x)^4 Just making sure this is right... I got tan(x)sec(x)^2 - (2/3) tan(x)^3 + C
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although, if you integrate it you do get sec(x)^4, so I guess it should be right.
I mean derive it. Not integrate it.
okk.. I used integration by parts.. but I also doubled checked with substitution and I got a different answer...
I've checked with wolfram, you probably got a different form, but it is correct.
oh okk thank you!
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\[{1 \over 3} (\cos(2 x)+2) \tan(x) \sec^2(x)+C\]is the original answer wolfram gave me, but it's equivalent to your initial solution.
thank you!! would you be able to look at another question? I've asked around and no one seems to have any idea....
sure
thank you.. let me post the link here...
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