Question

Calculus Help!!
If f′(x)=5xe^(x^2) and f(0)=0, then
f(x)=

Answer 1

Use substitution

u = x^2
du = 2x dx

Answer 2

punch what you have into the shape of U'.e^U which integrates into e^U
with f'(x) = (5/2).2x.e^(x^2) giving f(x) = (5/2).e^(x^2) + c
sub initial value to get at c.

Answer 3

that's what i did too....i put 2.5 and it is not correct!!

Answer 4

what did you put for the constant

--> 2.5e^0 +c = 0

Answer 5

-2.5 is not correct either

Answer 6

should i put 0?is the answer 0?

Answer 7

no -2.5 should be correct ??

Answer 8

it is incorrect for -2.5!!

Answer 9

http://www.wolframalpha.com/input/?i=y%27+%3D+5x*e^%28x^2%29%2C+y%280%29+%3D0

no it is correct

Answer 10

but it shows incorrect for it.stupid online assignment!!thanks anyways:)