Question

yx^3/(x^-3y^0 x x^-2y^2)^-2
Simplify your answer should contain only positive exponents.

Answer 1

I'm assuming that this the correct form of the expression:
\[yx^3/(x^{-3}.y^0.x^{-2}.y^2)^{-2}\]
anything to the power 0 is 1, so that y^0 just disappears,
combine the powers of x in the denominator to get x^(-5)
now apply the power of power in the whole denominator to get
\[yx^3/(x^{-5}.y^2)^{-2} = yx^3/(x^{10}.y^{-4})\]
now deal with combining the powers of x and powers of y from the top & bottom
\[y^{1--4}.x^{3-10} = y^5.x^{-7} = y^5/x^7\]