Question

Rationalize the denominator14(the index) to the sqrt of 3 / 3 (the index) to the sqrt of 7

Answer 1

I guess just multiply (sqrt(7)/sqrt(7)) times your fraction

Answer 2

and then you'll have (14*sqrt(3)*sqrt(7))/(3*7)

Answer 3

if they mean rationalize the denominator, then I'm sure you're just getting rid of the square root on the bottom but not dealing with sqrts on the top.

Answer 4

\[\frac{42\sqrt{21}}{63}\]

Answer 5

\[\frac{2\sqrt{21}}{3}\]

Answer 6

saifoo, you have 2 answers which one is correct

Answer 7

is the same like

3^(1/14) 7^(1/3) * 7^(1/3)* 3^(1/14) 7^(2/3) * 3^(1/14)
-------- = --------------------------- = -------------------- =
7^(1/3) 7^(1/3) *7^(1/3) *7^(1/3) (7^3)^(1/3)
cuberoot(7^2) * 14indexroot(3)
= ---------------------------
7

- so if the text of your exercise you have wrote it correct and if i have understood it right so than this will be the correct , right answer

Answer 8

ok ?

Answer 9

what is this ?

Answer 10

???