Question

what is the derivative of y = ((4-x)^2/x)?

a. 3 -(16/x^2)
b. 16x^2-3
c. 3x^2 - 16
d. (3/x^2)+6

Answer 1

i edit it because its very confusing the answer is not here.

Answer 2

y=(4x^2+2x)/x^2

=> y = 4x^2 / x^2 + 2x / x^2

=> y = 4 +...

Answer 3

((4-x)(4-x))/x^2

Answer 4

you need to use quotient rule
\[\frac{f}{g}' = \frac{f'g - fg'}{g^{2}}\]
f = (4-x)^2
g = x

f' use chain rule
u = 4-x
du = -1
d/du u^2 = 2u
--> f' = -2(4-x) = -8 +2x

g' = 1

Answer 5

uh...i got a -16/x^2 +1 when i expand and did it....i dunno, jst said it coz it seemed sorta close to the answers

Answer 6

yes mauve thats y im carefull all the answer are close that i wanted to choose letter E

Answer 7

i dunno, i tried the product and the quotient both....bt ddnt come close enuf. anyways goodluck :-)

Answer 8

yes the correct answer is (x^2-16)/x^2 or 1 - 16/x^2

Answer 9

ok im 100% sure i put letter E now