The function arccot is defined as the inverse of the cotangent function restricted to the interval (0,π). Suppose we define a function f by f(x)=cot(x) for x in the interval (2⋅π,3⋅π) and let g be the inverse function to f.

find g(-1)

Question

The function arccot is defined as the inverse of the cotangent function restricted to the interval (0,π). Suppose we define a function f by f(x)=cot(x) for x in the interval (2⋅π,3⋅π) and let g be the inverse function to f.

find g(-1)

anonymous · Answer

Hint: Substitute x with -1 for g(x) and evaluate. Do the same for g(√3).

anonymous · Answer

Suppose we define a function f by f(x)=cot(x) for x in the interval (2*π,3*π) and let g be the inverse function to f.
Give the domain of g.
Find the values of g⁡(sqrt(3))=
and g(⁡-1)=

anonymous · Answer

i found g(sqrt(3)) to be 13/6 pi but i cant find g(-1)

anonymous · Answer

Substitute it

anonymous · Answer

what is g(x) look like

ash2326 · Answer

$$f(x)=cot x$$
$$g(x)= 2\pi+ \cot^{-1} x$$
$$g(-1)=2pi+ \cot^{-1} (-1)$$
arccot -1= 3pi/4
so
$$g(-1)= 2\pi+3\pi/4$$

anonymous · Answer

thanks so much

dumbcow · Answer

y = f(x) = 1/tan(x)

--> tan(x) = 1/y
--> x = g(y) = arctan(1/y)

g(-1) = arctan(-1) = 3pi/4
in interval 2pi to 3pi,  add 2pi

2pi + 3pi/4 = 11pi/4

anonymous · Answer

ok i got it