Question

differentiate 7e^x^2

Answer 1

Here you just use the genral derivative to find e^x
For example
\[\int\limits_{}^{}e ^{x}dx = e ^{x}(x)\prime = e ^{x}(1)\]
So in this case
\[\int\limits_{}^{}7e ^{x ^{2}}dx=7\int\limits_{}^{}7e ^{x ^{2}}dx \]
7 is a constant
Now, \[7\int\limits_{}^{}e ^{x ^{2}}dx=7e ^{x ^{2}}(x ^{2})\prime\]
\[7e ^{x ^{2}}(x ^{2})\prime = 7e ^{x ^{2}}2x\]
Final answer,
\[\int\limits_{}^{}7e ^{x ^{2}}dx = 14xe ^{x ^{2}}\]

Answer 2

14X*e^[x^2] final ans
this is how u do it ....

Answer 3

7e^(x^2)(x^2)' that prime mean deff ==== 14*2x*e^[x^2]
u remember [x^2]'=2x? that is good... that is how u do it

Answer 4

the first ans myname did is intergration but your question ask for differentiation

Answer 5

I am very sorry that i mistakenly added the integration to it. It is like jmes said.
Thanks jmes

Answer 6

\[(7e ^{x ^{2}})\prime=7e ^{x ^{2}}(x ^{2})\prime\]
\[7e ^{x ^{2}}(x ^{2})\prime=7e ^{x ^{2}}(2x)=14x e ^{x ^{2}}\]