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OpenStudy (anonymous):
A 75.0-mL volume of 0.200M NH3 (Kb=1.8x10^-5) is titrated with 0.500M HNO3. Calculate the pH after the addition of 19.0mL of HNO3.
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OpenStudy (anonymous):
This will form a buffer do you know henderson's equation?
OpenStudy (anonymous):
the pH=pKa - log (A-/HA) ?
OpenStudy (anonymous):
yeah in this case it is a basic buffer so pOH=pKb+log A+/AOH
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Use Hvap of water = 40.7 kJ/mol, c of water = 4.184 J/g.u00b0C, and molar mass of HO = 18.
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