Question

What is the simplifie form of : [2x/3(x+3)]/[7x/(x+3)(x-5)].
I know that inorder to divide radicals you flip the second denominator and numerator so the new equation would be :
[2x/3(x+3)]*[(x+3)(x-5)/7x] However I do not know how to simplify the rest . Help ?

Answer 1

cancel out the (x+3)s
[2x/3]*[(x-5)/(7x)]
cancel out the xs
[2/3][(x-5)/7]
multiply them together:
2*(x-5)/21

Answer 2

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Answer 3

\[\frac{2x}{3(x+3)}\div\frac{7x}{(x+3)(x-5)}=\frac{2x}{3(x+3)}\times\frac{(x+3)(x-5)}{7x}\]

Answer 4

Now cancel x and x+3 and get:
\[\frac{2(x-5)}{21}\]

Answer 5

[2x/3(x+3)]/[7x/(x+3)(x-5)].
= [2x/3(x+3)] * (x+3)(x-5)/ 7x]
= 2 ( x- 5) / 21