Question

The boiling point of an aqueous solution is 101.02 °C. What is the freezing point?
H2O Kf=1.86 normal freezing pt= 0.00 Kb=0.512 normal bp= 100.00

Answer 1

\[\Delta T=k_{b} *m\]. So for boiling delta T is 1.02 and Kb is .512 so find m and then
plug it in \[\Delta T=k_{f} *m\]. to get delta T. Your answer should be negative or less than zero in other words