Question

(3-9i)-(5+6i)

is this -2-3i ??

Answer 1

yes and also

Answer 2

-2-15i

Answer 3

-2+3i^2

Answer 4

you know complex number i^2=-1

Answer 5

3-5-9i+6i=-2-3i which is also -2+3i^2

Answer 6

@jmes You sure about that?

Answer 7

so if i^2 is -1 then would it be 1 as the final answer?

Answer 8

On what basis did you square the i tru i^2 = -1 but what is the rationale for squaring it?

Answer 9

I see two expressions separated by a minus sign not a multiplication sign. The asker should straighten that out. Is this a subtraction problem or a multiplication problem?

Answer 10

yes I am

Answer 11

it based on complex number.... you should know that

Answer 12

check this
http://www.google.com/webhp?sourceid=chrome-instant&ix=seb&ie=UTF-8&ion=1#sclient=psy-ab&hl=en&site=webhp&source=hp&q=i%5E2&pbx=1&oq=&aq=&aqi=&aql=&gs_sm=&gs_upl=&fp=24e80911f62413e1&ix=seb&ion=1&ix=seb&ion=1&bav=on.2,or.r_gc.r_pw.,cf.osb&fp=24e80911f62413e1&biw=1366&bih=707&ix=seb&ion=1

Answer 13

3 - 5 = -2
-9i - 6i = - 15i
-2 - 15i

Answer 14

that site shown complex at very top....I confirmed to you now.

Answer 15

Assuming it is 1. a subtraction (3-9i)
-(5+6i)
-------
-2-15i

2. a multiplication problem:
(3-9i) X -(5+6i) = (3-9i) (-5-6i)=-15-18i+45i+54i^2 =-69+27i

Answer 16

@jmes I checked your reference link, and totally agree, but suggest you read it carefully.

Answer 17

Yes they are complex numbers that consist of both real and imaginary components. I suggest you treat them the way they should be treated.