Question

9+i / 9- i

Answer 1

9-8i/9

Answer 2

multiply top and bottom by the conjugate of 9 - i - that is 9 + i

Answer 3

i got 18i?

Answer 4

(9+i)(9+i)
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(9-i)(9+i)

Answer 5

or is it 1 + 18i ?

Answer 6

it is [i^2+18i+81]/80

Answer 7

= 81 +18i - 1
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81 - i^2

= 80 + 18i
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82

Answer 8

you should multiply with conjugate of the bottom and follow from there. the ans is the one i gave to you

Answer 9

it is [i^2+18i+81]/82 I made a little correction on my calculation this is it

Answer 10

you can simplify it a little by dividing by 2

(40 + 9i ) / 41

Answer 11

(81 + 18i - 1)/ (81 - (-1) ]= (80 +18i)/ 82

Answer 12

[9+i]/[9-1]*[9+i]/[9+i]= [81+9i+9i+i^2]/[81-[i^2=-1]

Answer 13

and final ans is[ i^2+18i+81/82

Answer 14

and final ans is[ i^2+18i+81]/82

Answer 15

right so far but you can simplify a bit further:
by definition i^2 = -1

Answer 16

if you want to Jummyrep that will give you [80+18]/82 final ans

Answer 17

you are very right Jimmyrep

Answer 18

ty