Question

x^3-x^2-16x+16

c=-4 is a zero

What are the remaining zeros?

What is this in full factored form?

Answer 1

factor as
\[x^3-x^2-16x+16 =(x+4)(\text{something})\] then use the quadratic formula. you can find the other factor by dividing, by synthetic division or by thinking.

Answer 2

x^2(x-1)-16(x-1)=(x-1)(x^2-16)=(x-1)(x-4)(x+4)

Answer 3

so the remaining zeros are 1, 4 and -4