Question

having trouble balancing the equation in the beginning of this problem. What volume in mL of 0.200 M NaOH do we need to titrate 35.00 mL of 0.140 M HBr to the equivalent point?

Answer 1

I don't know how to work the problem..but this is what i got for the balancing part

NaOH + HBr = H2O + NaBr

Everything seems to be already balanced there is no need for coefficients

Answer 2

okay thank you!

Answer 3

NaOH + HBr ---> NaBr + H2O
Moles of HBr: .035 * 0.140 M = .0049 mol
Volume of NaOH : .0049 / .2 = .0245L = 24.5 ml