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OpenStudy (anonymous):
Anyone Know how to do this kind of work that will help me through these problems would be really helpful!!!!!!!! 7( x - 1 ) ≥ -14
14 years ago
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OpenStudy (anonymous):
divide by 7 get
\[x-1\geq -2\] then add 1 to both sides to get
\[x\geq -1\]
14 years ago
OpenStudy (saifoo.khan):
\[x-1 \ge - \frac{14}{7}\]
\[x-1 \ge - 2\]
Add 1 on both sides,
\[x \ge -2 +1\]
\[x \ge Answer\]
14 years ago
OpenStudy (anonymous):
-3( x - 4 ) - 2( x + 4) ≤ 9
14 years ago
OpenStudy (anonymous):
7x-7>=-14; 7x>=-14+7; x>=-7/7; x>=-1
14 years ago
OpenStudy (anonymous):
-3( x - 4 ) - 2( x + 4) ≤ 9
14 years ago
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OpenStudy (anonymous):
\[x\geq -1\] as before
14 years ago
OpenStudy (anonymous):
5( x + 1) - 3( x - 1) > -9
14 years ago
OpenStudy (anonymous):
\[x\geq -\frac{17}{2}\]
14 years ago
OpenStudy (anonymous):
-3x+12-2x-8=<-9; -5x+4=<-9; -5x=<-4-9; -5x=<-13; (x-1)
x>=13/5
14 years ago
OpenStudy (anonymous):
4(x + 3) > 6(x - 5)
14 years ago
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OpenStudy (anonymous):
4x+12>6x-30; 4x-6x>-30-12; -2x>-42 (x-1) x<42/2; x<21
14 years ago
OpenStudy (anonymous):
x -1 >= -2
->x >= -1
14 years ago
OpenStudy (anonymous):
3x + 5 < 5
14 years ago
OpenStudy (anonymous):
In general you want to approach inequalities the same way that you would a simple equality however when you multiply or divide by a negative then you must change the direction of the inequality. i.e.) -x > 5 becomes x < 5.
14 years ago
OpenStudy (anonymous):
ok for 3x+ 5< 5 I got x ≥ -3
is that right ?
14 years ago
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OpenStudy (anonymous):
sorry -5(x + 3) ≥ 0 I got x ≥ -3
14 years ago
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