x/x+7 - 7/x-7 = x^2+49/x^2-49
My first step would be to find a common denominator for those fractions so I could add them. What would that look like?
(x+7) (x-7)?
That's the common denominator, yep! So how can you use that to add the fractions?
u use them as the base?
Yep, so for example, the first fraction will go from: \[\frac{x}{x+7} \Rightarrow \frac{?}{(x+7)(x-7)}\]What goes in place of the ?
will it be (x+7) +x-7 after factoring x^2+49
Unfortunately, x^2+49 cannot be factored.
What goes in place of that ? from before?
x-7
Close! Don't forget that there was an x there already.
7?
\[\frac{x}{x+7}=\frac{x}{x+7}\times\frac{x-7}{x-7}\]
so will that be x^2-7x/(x+7) (x-7)
x/x+7 - 7/x-7 = x (x-7) - 7 (x + 7) / (x^2 - 49 ) = x^2 - 14x + 49 / (x^2 - 49 ) Thus [x^2 - 14x + 49 / (x^2 - 49 ) ]= [(x^2 + 49) /(x^2 - 49 )] -> -14x / (x^2 - 49 )
so is the answer -14x/x^2-49
Yes!
thx so much
I'm glad I can help!
Once you have that, you can set it equal to the other side of the equation, and solve for x.
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