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OpenStudy (nenadmatematika):
you haven't written this properly...post again more carefuly :D
OpenStudy (anonymous):
Yeah, I can't read this.
OpenStudy (anonymous):
X Exp(x2+y) = y dy
OpenStudy (anonymous):
\[xe^{x^2+y} dx=ydy?\]
OpenStudy (anonymous):
sorry i'm new >> yeah that is right
please help me
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OpenStudy (anonymous):
That's okay, you will learn. Back to the DE in our hands. This DE is separable since we can write it as \(x(e^{x^2}e^y)dx=y dy.\). Divide both sides by \(e^y\) and then integrate both sides.
OpenStudy (anonymous):
Dividing both sides by \(e^y\) gives
\[xe^{x^2}dx=\frac{y}{e^y}dy \implies \int xe^{x^2}dx=\int ye^{-y}dy.\]
OpenStudy (anonymous):
Do you know how to evaluate the integrals?
OpenStudy (anonymous):
what (frac)
OpenStudy (anonymous):
What do you mean?
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OpenStudy (anonymous):
Hmm looks like your browser has some problems with showing latex. Anyways frac{x}{y} means x over y.
OpenStudy (anonymous):
what about Homogeneous ?
OpenStudy (anonymous):
What about it?
OpenStudy (anonymous):
can solve with it ?
is that Homogeneous Eq.?
OpenStudy (anonymous):
It doesn't look homogeneous to me.
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OpenStudy (anonymous):
if it ? how i solve in this way?
and can you help me to get me book with maths Eq.
OpenStudy (anonymous):
Are you asking about how to solve Homogeneous DE's?