Question

Integral sec t (tan t)^2 dt

Answer 1

u = sect

Answer 2

hah, you got that from that sqrt(x-2)/sqrt(x-1) thing, right?

Answer 3

sect(tan^2t)=sect(sec^2t-1)=sec^3t-sect

Answer 4

I did

Answer 5

\[\int\sec^3 tdt\]\[u=\sec t\]\[dv=\sec^2 t\]integrate by parts

Answer 6

I've gotten that far in the equation already, just not sure what to do with the sec^3 t

Answer 7

ah, okay.

Answer 8

^there it is
this will be one of those integrals that repeats, so you will wind up adding the integral of sec^3 to both sides
you will still have to integrate sec though, hope you remember how to do that ;)

Answer 9

I do :)

Answer 10

correst