Can anyone help me with this one please simplify 3/5+(-1/7) all over 1and1/2
\[\frac{\frac{3}{5}-\frac{1}{7}}{1\frac{1}{2}}\] ?
if so, make the denominator an improper fraction \[ 1 \frac{1}{2}= \frac{3}{2} \] multiply top and bottom by 2/3 to get rid of the denominator \[\frac{(\frac{3}{5}-\frac{1}{7})\cdot \frac{2}{3}}{\cancel{\frac{3}{2}}\cdot\cancel{\frac{2}{3}}}\]
Can you finish this?
I'll give it a try
video on adding fractions http://www.khanacademy.org/video/adding-fractions-with-unlike-denominators?topic=fractions
multiplying fractions http://www.khanacademy.org/video/multiplying-fractions?topic=fractions
If I did this correctly the answer would be 32/105 ?
Thanks for the links
\[(\frac{3}{5}-\frac{1}{7})= \frac{3}{5}\cdot\frac{7}{7}-\frac{1}{7}\cdot \frac{5}{5}= \frac{21}{35}-\frac{5}{35}\]
which becomes 16/35 times 2/3 = 32/105
Looks like you know what you are doing.
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