Two charges are placed at the corners of an equilateral triangle that is 0.25 m on each side. The first charge is 4.5 μC and the second is 3.2 μC. If a charge if 2.5 μC is placed at the third corner of the triangle, what is the magnitude of the electric force on the third charge due to the first two charges?

A) 1.96 N

B) 0.602 N

C) 3.19 N

D) 2.41 N

E) 4.31 N

Question

Two charges are placed at the corners of an equilateral triangle that is 0.25 m on each side. The first charge is 4.5 μC and the second is 3.2 μC. If a charge if 2.5 μC is placed at the third corner of the triangle, what is the magnitude of the electric force on the third charge due to the first two charges? 

 
A) 1.96 N
 
B) 0.602 N
 
C) 3.19 N
 
D) 2.41 N
 
E) 4.31 N

anonymous · Answer

YOu count the force between  4.5 charge and the 2.5   F 1 
then you cound the force between 3.2 and 2.5   F 2

adad F1 + F2 you got your solution

sanaelshazly · Answer

I didn't get you actually !!

anonymous · Answer

Do you know how to get the force between two charges if you dont then you wont get me 

You find the force between the two charges F = K *q1 * q2/ r ^2  I dont remeber the equation  then sub the values for q1  and q 3 then  q 2 and q 3

anonymous · Answer

Then add the results   from the substitution

anonymous · Answer

can any one tell me what the final answer will be ?