Let R be the region in the xy-plane between the graphs of y = ex and y = e-x from x = 0 to x = 2.
a) Find the volume of the solid generated when R is revolved about the x-axis.

Question

Let R be the region in the xy-plane between the graphs of y = ex and y = e-x from x = 0 to x = 2.
	a) Find the volume of the solid generated when R is revolved about the x-axis.

accessdenied · Answer

Do you mean..
$$ \begin{split}
y &= e^{x} and\
y &= e^{-x}\
\end{split}$$
?

anonymous · Answer

yes

accessdenied · Answer

$$
\begin{align}
&\int_{a}^{b} (y_{1}^{2} - y_{2}^{2}) dx; y_{1} = e^{x}, y_{2} = e^{-x}, a=0, b=2\
&\
&\
&\
&\int_{0}^{2} ( (e^{x})^{2} - (e^{-x})^{2} ) dx
\end{align}
$$

anonymous · Answer

thank you

rulnick · Answer

Is this the one?

accessdenied · Answer

d'oh i missed the pi here!

rulnick · Answer

Spoken like Homer.

accessdenied · Answer

unfortunately, its too late to correct it... i hope he did figure it out himself  :(

rulnick · Answer

tserio94, I'm not sure whether you have this done yet or not, or if any of your classmates have it, but I did it and get a different setup and different solution. let me know.  or if amistre64 or others know if the solution has or has not been posted, please let me know. thanks.

accessdenied · Answer

amistre64 posted a solution and was linking everybody asking this to the post

anonymous · Answer

can you help me throw it

accessdenied · Answer

http://openstudy.com/users/amistre64#/updates/4f4c1eb8e4b0acf2d9fd9e32 this was the link amistre64 posted about the problem, you may have to backtrack through the same question being asked and being redirected further.. lol

anonymous · Answer

yeah but can you help me through it

rulnick · Answer

You there, t94?

anonymous · Answer

yes

anonymous · Answer

can you explain how you get the 1/2 part when you intergrate it