Question

Find the number of solutions for the given equation for 0° ≤ θ ≤ 360°.

sin2x - 2sinx - 3 = 0

Answer 1

is the equation\[\sin^2 x - 2sinx - 3=0\]

Answer 2

yes

Answer 3

Its a quadratic in "sin(x)". Solve for the roots of the quadratic. Then, use inverse of sine to find x.

Answer 4

you need to factorise the quadratic and solve.... but there is only 1answer to the problem x = 270

Answer 5

This is supposed to be a Trigonometric Equation.

Answer 6

It is a qudratic equation with trigonometric function in its terms.

Answer 7

the factorisation is (sin x -3)(sinx + 1) = 0

Answer 8

Since sin(x) can't be 3 ever, it only has one solution, which is sin(x) = -1 => x = 270 degrees.