Starting with V=Voe^(-t/RC) show that t(.5)= RCln2. This is an analysis question for a lab on RC circuits w/ AC. I don't quite understand the question.

Question

jamesj · Answer

It's asking you for what time, t, is $ V = V_0/2 $.

anonymous · Answer

So what I plug in the Voltage, Vo/2 and it should be the same as RCln(2)?

jamesj · Answer

No, you want the value of $ t $ for which $ V = V_0/2 $.  In other words, the value of $ t $ for which

$$ \frac{V_0}{2} = V_0 e^{-t/RC} $$
Solve that equation for $ t $.

anonymous · Answer

So something  like .5= e^-t/RC  -> ln(.5) =-t/RC -> -(1/t) = 1/RCln(.5) -> t=RCln(.5)?

jamesj · Answer

From here,
ln(.5) =-t/RC 
remember that ln(1/2) = -ln(2)

anonymous · Answer

Oh yea, thanks got it.