Question

How to calculate mass of .35L of H2O?

Answer 1

If you're assuming room temperature in the liquid state at atmospheric pressure we can safely say approximately that 1 mL of water = 1 cm^3 water = 1 g water.

Answer 2

Oh so it equals 350grams then?

Answer 3

\[D=\frac{m}{V} \rightarrow m=DV\]\[m=(\frac{1.00g}{1.00mL})*(350mL)=350g\]Yes.