Question

I have only 2 attempts to get this correct...
This is involving a basketball player's
three point shooting. Assume that his shots are Bernoulli trials, and that he makes 1 in 7 of his shots.
How many three point shots must the player attempt so that the probability of
his hitting at least one of them is at least 0.93?

Answer 1

at least one, means not none. none is
\[(\frac{6}{7})^n\] for n trials. so we need
\[(\frac{6}{7})^n<.07\]

Answer 2

i get n = 18 by trial and error

Answer 3

this will assure that
\[1-(\frac{6}{7})^n>.93\] i think
we can solve exactly using logarithms, but since n is an integer trial and error seems best

Answer 4

So try 18

Answer 5

you can change 18 to a different number and experiment
http://www.wolframalpha.com/input/?i=%286%2F7%29^18

Answer 6

I did some by trial and error but mostly through formulas

Answer 7

you were right

Answer 8

imagine!