There are 52 white keys and 36 black keys on a standard piano. What is the probability that if a person did not look and hit the keyboard twice that he or she would first hit a white key and then hit a black key?

Question

There are 52 white keys and 36 black keys on a standard piano.  What is the probability that if a person did not look and hit the keyboard twice that he or she would first hit a white key and then hit a black key?

anonymous · Answer

$$\frac{52}{88}\times \frac{36}{88}$$ maybe can reduce

kinggeorge · Answer

There are a total of $52+36=88$ keys on the piano. Thus, the probability of hitting a white key would be $52 \over 88$ and a black key $36 \over 88$ Therefore, the probability of hitting a white key then a black key is given by $${52 \over 88} \times {36 \over 88}$$

anonymous · Answer

thank you for explaining it too me :) its easier to understand now how to do the problem

kinggeorge · Answer

you're welcome

anonymous · Answer

So the answer is 1/1872 probablity?

anonymous · Answer

Could someone help me  with this , because I got 117/484.

kendricklamar2014 · Answer

$$\frac{ 52 }{ 88 } \times \frac{ 36 }{ 88 } = \frac{ 117 }{ 484 }$$

kendricklamar2014 · Answer

Just clarifying the answer ;)