what is the equation for this: two positively charged particles with respective charges of 0.02 and 0.05C are placed 2cm apart. what is the intensity of the electricalforce each particle exerts on the other?

Question

mertsj · Answer

I can't quite remember this formula.  don't you have it?  Something about inversely proportional to the square of the distance between them???

rulnick · Answer

F = k q1 q2 / r^2,

rulnick · Answer

where q1 and q2 are the two charges and r is the distance between them.

anonymous · Answer

what does k stand for?

rulnick · Answer

k = 1 / (4 pi epsilon0)
and epsilon0 = permittivity of free space.

rulnick · Answer

Permittivity of free space = 8.85419 x 10^(-12) C^2/N m^2.

anonymous · Answer

im only grade 10 science. we are just starting this unit. anything easier?

rulnick · Answer

All right, hang on.

anonymous · Answer

thank you!!!

rulnick · Answer

It's just 9 billion times the product of the two charges, divided by the square of the distance between them, as long as the charges are in C and distances are in m.

anonymous · Answer

perfect awesome thanks!

rulnick · Answer

So for your distance, use 0.02 (meters) not 2 (cm).