Question

5y^-2 + 1= 6y^-1

how do you solve it by step?

Answer 1

y=1,5

Answer 2

I mean step

Answer 3

plug in the value

Answer 4

little lost on the "plug in the value" can you give me a example?

Answer 5

Take this 5y^-2 and 6y^-1 Subtract it

Answer 6

\[\frac{5}{y^2}+1=\frac{6}{y}\] is how i read it. is that wrong?

Answer 7

yea

Answer 8

sorry my computer is acting up

Answer 9

ok so maybe
\[1=\frac{6}{y}-\frac{5}{y^2}\]
\[1=\frac{6y-5}{y^2}\]
\[y^2=6y-5\]
\[y^2-6y+5=0\]
\[(y-5)(y-1)=0\]
\[y=5, y=1\]

Answer 10

That the part what I'm missing thanks