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A 10-V battery is connected to an RC circuit (R = 6 Ω and C = 10 μF). Initially, the capacitor is uncharged. What is the final charge on the capacitor (in μC)?
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post this in physics dude
Multiply the battery voltage in V by the capacitance in F to get the final charge in C.
So in your case, 10 (10 x 10^(-6) ) = 10^(-4) C or 100 microC.
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