Find the vector V with the given length that has the same direction as U: ||V||=4 U=(=1,1)
4*u/|u|
ohhh i get it. thanks :DDDDD
aww... i could have helped pippa :(
you still can ;)
r u sure?
is that a -1,1 ?
cuz like for another example the book gives a diff answer
|u| = sqrt(2) unit u = <1/sqrt(2), 1/sqrt(2)> scale by 4 to get: <4/sqrt(2), 4/sqrt(2)> and simplify if needed
im sure, as long as you got the right stuff: in essesne; unit the vector and scale it to the desired magnitude
\[\frac{|v|}{|u|}\vec{u}\]
sorry os just froze on me I am gonne read it now
idk its wierd
so let me give u the example: ||V||=4 u=(1,1) the answer is 2sqrt(2), ssqrt(2)
yes
|u| = sqrt(2) sqrt(2)/sqrt(2) = 1 so we divide the vector by its own magnitude to keep its direction by to shorten it to 1
then we simply scale it up by how big |v| is
hehe i am halfway sleeping. Guess i just need to sit over it
how many feet are in a yard stick?
idk lol ohhh 3
right 3 feet; and if you only want 1 foot; you divide the yard stick by what number?
hehe 3
yep, thats all we are doing to get a "unit" length vector; dividing it by its magnitude
ok thanks
hahahahahaha i got it amistre lol
Yay sorry i was on the slow side. I am barely functioning. It was like basic math operations
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