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OpenStudy (anonymous):
Final question for me.
See graph attached
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OpenStudy (anonymous):
Let g(x) = \[\int\limits_{0}^{x}f(x)dx\]
Find: \[\int\limits_{0}^{5}f(x)dx\]
OpenStudy (anonymous):
Why not just use triangles and rectangles to get the area under the function?
OpenStudy (anonymous):
I have thought of breaking it into three parts
finding the area from 0 to 2, 2 to 4 and 4 to 5
is this right?
OpenStudy (anonymous):
x=4->x=5 is a rectangle
OpenStudy (anonymous):
\[\int^5_0 f(x) dx = 2*1/2+3*2/2+1*3=1+3+3=7\]
Correct @afternoonmrmoon
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OpenStudy (anonymous):
Triangle = B*H/2, Rectangle=L*W
OpenStudy (anonymous):
x=2->4 is a right triangle as is x=0->2
OpenStudy (anonymous):
zed could you explain what you did there
its hard to see what you wrote.
OpenStudy (anonymous):
ah I see what you did
OpenStudy (anonymous):
That makes much more sense
Thanks Zed. :)
one quick question if I wanted to find the integral of g"(x) would that be just the integral of g'(x)?
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OpenStudy (anonymous):
\[\int g''(x) dx=g'(x)+C\]
OpenStudy (anonymous):
Thanks a bunch :)
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