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Mathematics 8 Online
OpenStudy (anonymous):

Find the derivative of the trigonometric function. f(x)=-x+tanx

OpenStudy (mimi_x3):

Well, the derivative of tanx = sec^2x. so.. \[f'(x) = -1 + \sec^2x\]

OpenStudy (anonymous):

hmmmm how do i knw the derivative of tanx = sec^x?

Directrix (directrix):

y' =sec²x - 1 http://www.wolframalpha.com/input/?i=derivative+of+y+%3D-x+%2B+tan%28x%29

OpenStudy (mimi_x3):

Well, you have to like memorise the derivative of it.

OpenStudy (anonymous):

and the book says tan^2x so i assume sec^2x -1 = tan^2x

OpenStudy (mimi_x3):

Yes. Its a trig identity.

OpenStudy (anonymous):

oh i belive mimi just asking for my knowledge

OpenStudy (anonymous):

dont want someone just doing my homework for me

OpenStudy (anonymous):

lol

OpenStudy (anonymous):

id rather learn then just write down the correct answer :)

Directrix (directrix):

You have to know the basic trig identities. Just a few of them and they are related.

OpenStudy (anonymous):

i am just wondering why my book doesnt tell me this before asking this question

OpenStudy (anonymous):

oh i know the trig identities but not the derivatives

OpenStudy (anonymous):

like i know 1-sin^2 = cos^2

Directrix (directrix):

http://www.math.com/tables/derivatives/more/trig.htm

OpenStudy (anonymous):

but that didnt teach me the derivative of cos^2

OpenStudy (anonymous):

thanks i looked at it :)

OpenStudy (anonymous):

so i need to memorize these too?

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